Example H6.10
Matlab code for example 6.10 from the book "Regeltechniek voor het HBO"
Determination of the root locus gain graphically or through basic insight
- Date : 02/03/2022
- Revision : 1.0
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Static accuracy in a given point on the rootlocus
Suppose the transfer function of in figure 6.4 equals: . The root locus of the feed back systeem is shown in figure 6.11.
The pole position (and also the complex conjugated ) corresponds to a damping factor (see section 4.4). What is the static accuracy in that point?
Solution 1
In figure 6.11 we can use formula 6.46 to calculate the root locus gain :
. For the static gain of the loop we can use formula 6.48: . So the static error in a step response will be (see the text preceding formula 6.47): . Solution 2
Instead of using all those formulas there is another way, simply based on the basic knowledge we have got:
First of all we have to remember the "final value theorem" of Laplace:
. For the step response of a system with transfer function and input , so , this means: . So if we we want to know the static behaviour of a system (this only makes sense with a constant input of course, a step), we only have to substitute in , or for further calculations in all partial transfer functions of the system for further calculations. In our case this means for : . The only thing left for us to do is determing from the root locus equation in (or , that doesn't matter): From the root locus equation:
→ → . So a step 1 generates in the static state in output of only , and that is too little for what we would ideally like. So the static error is 32%, or the static accuracy is 68%. Matlab code for this example
% clear all variables from Workspace and close all figures.
% Create the 2nd order proces
% Show the root locus plot of H
% Show stepresponse and static error