Example H4.8

MATLAB code for example 4.8 from the book "Regeltechniek voor het HBO"

Experimental determination of the transferfunction from the step response

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Table of Contents

Determine three parameters from the step response

Suppose in figure 4.25 the step response with step size 4 has a result as shown in figure 4.26. Because of the overshoot we clearly see that this response is part of a (at least dominant) second order process with damping factor . The horizontal start of the response in underlines the second order behaviour. Figure 4.26 immediately shows the relevant values of the static amplification , overshoot D and period time of the oscillation:

Calculate the parameters

From this we can perform all calculations in a certain sequence (see formula sheet in appendix D):
From : rad/s.
From =0.4:
; as λ is negative .

Calculate the parameters β and

From
(a negative β is physically not possible).
(maybe the formula had been preferrable in this case; now to late!)
From : rad/s.
From :

In summary

We derrived two sets of parameters:
() = (6.72, -0.46, 1.57)
() = (2.5 0.29, 1.64)
In transfer function (see 4.11):
You can check again the solution by simulating the step response in MATLAB (step size 4 of the input!) and compare the result with figure 4.26. You can do it yourself now, or see the previous examples of this chapter.
In this example we had to do a lot of calculations. To a certain extent that is secondary. What matters is understanding the theory, especially the physical and /or mathematical meaning of the parameters and .